HEXAWARE GD Topics »
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1. Everybody jumping into software field - is it good or bad.
2. “EDUCATION AND SUCCESS” DOES IT HAVE A CORRELATION.
3. “Whether impact of western culture on Indian culture is a boon or a bane”.
4. Is internet suitable for Younger’s?
5. IS MBA needed?
6. What Should India do to win a gold medal in the Olympics?
7. Will India need a Dictatorship / Democratic rule now?
8. “Two solutions to improve engineering standard”
1. Everybody jumping into software field - is it good or bad.
2. “EDUCATION AND SUCCESS” DOES IT HAVE A CORRELATION.
3. “Whether impact of western culture on Indian culture is a boon or a bane”.
4. Is internet suitable for Younger’s?
5. IS MBA needed?
6. What Should India do to win a gold medal in the Olympics?
7. Will India need a Dictatorship / Democratic rule now?
8. “Two solutions to improve engineering standard”
It would be Great..............
Marhaba,
Brilliant article, glad I slogged through the #topic it seems that a whole lot of the details really come back to from my past project.
I made a basic calculator using this codes. What i want to learn is how to make a loop after the program ask "try again y/n"? it will return to choose an operation.
Code:
#include
#include
int main(){
int num1, num2, choice;
printf("Choose an operation\n\n");
printf("[1] Add\n[2] Subtract\n[3] Multiply\n[4] Divide\n[5] Exit\n");
scanf("%d", &choice);
switch(choice){
case 1:
printf("Enter 1st number:\n");
scanf("%d", &num1);
printf("Enter 2nd number:\n");
scanf("%d", &num2);
printf("\n%d", (num1+num2));
break;
case 2:
printf("Enter 1st number:\n");
scanf("%d", &num1);
printf("Enter 2nd number:\n");
scanf("%d", &num2);
printf("\n%d ", (num1-num2));
break;
case 3:
printf("Enter 1st number:\n");
scanf("%d", &num1);
printf("Enter 2nd number:\n");
scanf("%d", &num2);
printf("\n%d", (num1*num2));
break;
case 4:
printf("Enter 1st number:\n");
scanf("\n%d", &num1);
printf("Enter 2nd number:\n");
scanf("%d", &num2);
printf("\n%d", (num1/num2));
break;
case 5:
return 0;
default:
printf("That is not a valid choice.");
break;
}
getch();
}
Awesome! Thanks for putting this all in one place. Very useful!
Thanks a heaps,